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For Q4 I think it depends on the load, how much current the load needs. The purpose of R8 is to make sure Q4 is off when not being explicitly driven. Please post the readings and I’ll try to help you find a replacement. Something in the 2. That pulls the top end of R4 which, which turns on Q1.
The LED D1 is used as an example of a load. Log in to post comments. I’m not a fan of the 5. That means a total of at least 1.
Jax edited the first few lines “removed that is”. The base of Q1 needs 2.
Home Questions Tags Users Unanswered. Hope this helps you out. I would use 1. The circuits very likely will work but I would not say either circuit in the question is “well designed” or very “robust”. Once you understand what each part does, you’ll be able to find acceptable values for them yourself. Thanks for the feed back.
Anyone know where I can pick up one of these bad boys? I think that for both sets of resistor values the latch will work.
From inspection, we can see that the current to drive Q2 can be much smaller than that. So now you should be able to see for yourself what a good range of values for the resistors are.
Sign up or log in Sign up using Google. Let’s therefore work backwards requiring Q1 to sink 2. The load is a unspecified LED emitting visible light. Also from what I’ve read, Ge transistors are prone to eairly demise. Changing R2, R3 will make the latch work or not.
I thank you for having responded to my question. Added You now say that you want to support a final load current of mA, and that the gain of Q4 is Content is read only for historical purposes.
That shorts the base of Q1 to ground, turning it off. Let’s say now B-E is mV. I can’t find a relacement or equivilent. I would therefore use 3. Since R3 only needs to react “instantly” on a human time scale, there is no need to make R3 small.
Instead of just poking at random values and asking what difference they make, stop and actually think about the circuit. Note how the suggested by OP resistor values aren’t that well chosen.
When SW2 is pressed, it turns on Q3. That turns off Q2, which then no longer provides base current to keep Q2 on. Post as a guest Name.
The main job of Q1 is to turn on Q4, so it can power the load. That results in Email Required, but never shown.
That large current isn’t really needed. You haven’t provided a datasheet for the 2SA, so we’ll arbitrarily assume they can be counted on to have a gain of at least To do even better I’d use some CMOS logic based circuit because that will be miles better regarding power consumption. When SW1 is pressed for a little while, Q1 is datasheeet on. Soldered it in and voila, works perfectly.